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1334212443041 is a prime number
BaseRepresentation
bin10011011010100101010…
…000100011101110100001
311201112211120002122010012
4103122211100203232201
5133324431341134131
62500532335014305
7165252012434312
oct23324520435641
94645746078105
101334212443041
11474922161005
121966b506a395
1398a7b103a8a
144880d248609
1524a8c78a52b
hex136a5423ba1

1334212443041 has 2 divisors, whose sum is σ = 1334212443042. Its totient is φ = 1334212443040.

The previous prime is 1334212443037. The next prime is 1334212443071. The reversal of 1334212443041 is 1403442124331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 954781082641 + 379431360400 = 977129^2 + 615980^2 .

It is a cyclic number.

It is not a de Polignac number, because 1334212443041 - 22 = 1334212443037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1334212442989 and 1334212443007.

It is not a weakly prime, because it can be changed into another prime (1334212443001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667106221520 + 667106221521.

It is an arithmetic number, because the mean of its divisors is an integer number (667106221521).

Almost surely, 21334212443041 is an apocalyptic number.

It is an amenable number.

1334212443041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1334212443041 is an equidigital number, since it uses as much as digits as its factorization.

1334212443041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 1334212443041 its reverse (1403442124331), we get a palindrome (2737654567372).

The spelling of 1334212443041 in words is "one trillion, three hundred thirty-four billion, two hundred twelve million, four hundred forty-three thousand, forty-one".