Base | Representation |
---|---|
bin | 1100001000100111010011… |
… | …1111111010000011100100 |
3 | 1202020111101001221221102101 |
4 | 3002021310333322003210 |
5 | 3222044141110100200 |
6 | 44213142430221444 |
7 | 2544636311053522 |
oct | 302116477720344 |
9 | 52214331857371 |
10 | 13342131331300 |
11 | 4284403342862 |
12 | 15b5964954884 |
13 | 75a2082a7355 |
14 | 341a96819312 |
15 | 1820d59d326a |
hex | c2274ffa0e4 |
13342131331300 has 36 divisors (see below), whose sum is σ = 28952818550320. Its totient is φ = 5336779986720.
The previous prime is 13342131331279. The next prime is 13342131331327. The reversal of 13342131331300 is 313313124331.
13342131331300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×133421313313002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6813487 + ... + 8550313.
Almost surely, 213342131331300 is an apocalyptic number.
13342131331300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13342131331300 is an abundant number, since it is smaller than the sum of its proper divisors (15610687219020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13342131331300 is a wasteful number, since it uses less digits than its factorization.
13342131331300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1813660 (or 1813653 counting only the distinct ones).
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 13342131331300 its reverse (313313124331), we get a palindrome (13655444455631).
The spelling of 13342131331300 in words is "thirteen trillion, three hundred forty-two billion, one hundred thirty-one million, three hundred thirty-one thousand, three hundred".
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