Base | Representation |
---|---|
bin | 1100001000101000000011… |
… | …1010111001010101010110 |
3 | 1202020111220000022122120002 |
4 | 3002022000322321111112 |
5 | 3222100043311003324 |
6 | 44213214333211302 |
7 | 2544644260123535 |
oct | 302120072712526 |
9 | 52214800278502 |
10 | 13342331344214 |
11 | 42844a6234494 |
12 | 15b59bb930b32 |
13 | 75a23a8674a2 |
14 | 341ab520231c |
15 | 1820e83413ae |
hex | c2280eb9556 |
13342331344214 has 4 divisors (see below), whose sum is σ = 20013497016324. Its totient is φ = 6671165672106.
The previous prime is 13342331344201. The next prime is 13342331344219. The reversal of 13342331344214 is 41244313324331.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13342331344219) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3335582836052 + ... + 3335582836055.
It is an arithmetic number, because the mean of its divisors is an integer number (5003374254081).
Almost surely, 213342331344214 is an apocalyptic number.
13342331344214 is a deficient number, since it is larger than the sum of its proper divisors (6671165672110).
13342331344214 is an equidigital number, since it uses as much as digits as its factorization.
13342331344214 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6671165672109.
The product of its digits is 248832, while the sum is 38.
Adding to 13342331344214 its reverse (41244313324331), we get a palindrome (54586644668545).
The spelling of 13342331344214 in words is "thirteen trillion, three hundred forty-two billion, three hundred thirty-one million, three hundred forty-four thousand, two hundred fourteen".
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