Base | Representation |
---|---|
bin | 1100001000101000000110… |
… | …1000100110000101110111 |
3 | 1202020111220211212021202201 |
4 | 3002022001220212011313 |
5 | 3222100104342332043 |
6 | 44213215442045331 |
7 | 2544644464010230 |
oct | 302120150460567 |
9 | 52214824767681 |
10 | 13342343324023 |
11 | 4284501a7705a |
12 | 15b5a03949847 |
13 | 75a2401a022c |
14 | 341ab6a40087 |
15 | 1820e940ac4d |
hex | c2281a26177 |
13342343324023 has 32 divisors (see below), whose sum is σ = 15822419558400. Its totient is φ = 11013875389440.
The previous prime is 13342343323993. The next prime is 13342343324081. The reversal of 13342343324023 is 32042334324331.
It is a de Polignac number, because none of the positive numbers 2k-13342343324023 is a prime.
It is a super-2 number, since 2×133423433240232 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13342343324923) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6333615 + ... + 8173087.
It is an arithmetic number, because the mean of its divisors is an integer number (494450611200).
Almost surely, 213342343324023 is an apocalyptic number.
13342343324023 is a deficient number, since it is larger than the sum of its proper divisors (2480076234377).
13342343324023 is a wasteful number, since it uses less digits than its factorization.
13342343324023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1839847.
The product of its (nonzero) digits is 373248, while the sum is 37.
Adding to 13342343324023 its reverse (32042334324331), we get a palindrome (45384677648354).
The spelling of 13342343324023 in words is "thirteen trillion, three hundred forty-two billion, three hundred forty-three million, three hundred twenty-four thousand, twenty-three".
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