133424141423819 has 2 divisors, whose sum is σ = 133424141423820. Its totient is φ = 133424141423818.

The previous prime is 133424141423813. The next prime is 133424141423821. The reversal of 133424141423819 is 918324141424331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133424141423819 is a prime.

It is a super-2 number, since 2×133424141423819² (a number of 29 digits) contains 22 as substring.

Together with 133424141423821, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133424141423813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66712070711909 + 66712070711910.

It is an arithmetic number, because the mean of its divisors is an integer number (66712070711910).

Almost surely, 2^{133424141423819} is an apocalyptic number.

133424141423819 is a deficient number, since it is larger than the sum of its proper divisors (1).

133424141423819 is an equidigital number, since it uses as much as digits as its factorization.

133424141423819 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1990656, while the sum is 50.

The spelling of 133424141423819 in words is "one hundred thirty-three trillion, four hundred twenty-four billion, one hundred forty-one million, four hundred twenty-three thousand, eight hundred nineteen".