Base | Representation |
---|---|
bin | 11110010101100100111010… |
… | …100011011101011100000111 |
3 | 122111102020000211012100201001 |
4 | 132111210322203131130013 |
5 | 114442010120201040031 |
6 | 1151434112052114131 |
7 | 40050401414452216 |
oct | 3625447243353407 |
9 | 574366024170631 |
10 | 133424141424391 |
11 | 39570951523804 |
12 | 12b6a5ab005947 |
13 | 595aac510820c |
14 | 24d3a9758907d |
15 | 1065a04d10861 |
hex | 79593a8dd707 |
133424141424391 has 2 divisors, whose sum is σ = 133424141424392. Its totient is φ = 133424141424390.
The previous prime is 133424141424269. The next prime is 133424141424421. The reversal of 133424141424391 is 193424141424331.
It is a strong prime.
It is an emirp because it is prime and its reverse (193424141424331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133424141424391 - 215 = 133424141391623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133424141524391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66712070712195 + 66712070712196.
It is an arithmetic number, because the mean of its divisors is an integer number (66712070712196).
Almost surely, 2133424141424391 is an apocalyptic number.
133424141424391 is a deficient number, since it is larger than the sum of its proper divisors (1).
133424141424391 is an equidigital number, since it uses as much as digits as its factorization.
133424141424391 is an evil number, because the sum of its binary digits is even.
The product of its digits is 995328, while the sum is 46.
The spelling of 133424141424391 in words is "one hundred thirty-three trillion, four hundred twenty-four billion, one hundred forty-one million, four hundred twenty-four thousand, three hundred ninety-one".
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