Base | Representation |
---|---|
bin | 1100001000101010111101… |
… | …1010010100010111001011 |
3 | 1202020120220101000012110121 |
4 | 3002022233122110113023 |
5 | 3222103143000131243 |
6 | 44213423555124111 |
7 | 2545002510664342 |
oct | 302125732242713 |
9 | 52216811005417 |
10 | 13343111333323 |
11 | 4284866547892 |
12 | 15b5b98ba3637 |
13 | 75a333331cc5 |
14 | 341b4aa3cb59 |
15 | 182141a641ed |
hex | c22af6945cb |
13343111333323 has 2 divisors, whose sum is σ = 13343111333324. Its totient is φ = 13343111333322.
The previous prime is 13343111333297. The next prime is 13343111333351. The reversal of 13343111333323 is 32333311134331.
13343111333323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13343111333323 - 25 = 13343111333291 is a prime.
It is not a weakly prime, because it can be changed into another prime (13343111333423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671555666661 + 6671555666662.
It is an arithmetic number, because the mean of its divisors is an integer number (6671555666662).
Almost surely, 213343111333323 is an apocalyptic number.
13343111333323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13343111333323 is an equidigital number, since it uses as much as digits as its factorization.
13343111333323 is an evil number, because the sum of its binary digits is even.
The product of its digits is 52488, while the sum is 34.
Adding to 13343111333323 its reverse (32333311134331), we get a palindrome (45676422467654).
The spelling of 13343111333323 in words is "thirteen trillion, three hundred forty-three billion, one hundred eleven million, three hundred thirty-three thousand, three hundred twenty-three".
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