Base | Representation |
---|---|
bin | 11000110110101000… |
… | …00001011010101001 |
3 | 1021102220110111202001 |
4 | 30123110001122221 |
5 | 204311320313101 |
6 | 10044005411001 |
7 | 651440531251 |
oct | 143324013251 |
9 | 37386414661 |
10 | 13343135401 |
11 | 5727941132 |
12 | 2704709a61 |
13 | 13484c34bb |
14 | 90816a961 |
15 | 531631901 |
hex | 31b5016a9 |
13343135401 has 2 divisors, whose sum is σ = 13343135402. Its totient is φ = 13343135400.
The previous prime is 13343135381. The next prime is 13343135417. The reversal of 13343135401 is 10453134331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11782885401 + 1560250000 = 108549^2 + 39500^2 .
It is a cyclic number.
It is not a de Polignac number, because 13343135401 - 25 = 13343135369 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13343135401.
It is not a weakly prime, because it can be changed into another prime (13343135431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671567700 + 6671567701.
It is an arithmetic number, because the mean of its divisors is an integer number (6671567701).
Almost surely, 213343135401 is an apocalyptic number.
It is an amenable number.
13343135401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13343135401 is an equidigital number, since it uses as much as digits as its factorization.
13343135401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 13343135401 its reverse (10453134331), we get a palindrome (23796269732).
The spelling of 13343135401 in words is "thirteen billion, three hundred forty-three million, one hundred thirty-five thousand, four hundred one".
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