Base | Representation |
---|---|
bin | 11110010101101101001101… |
… | …001001000111111000000011 |
3 | 122111110002000012111112101111 |
4 | 132111231031021013320003 |
5 | 114442131333031101034 |
6 | 1151442143244344151 |
7 | 40051135125466042 |
oct | 3625551511077003 |
9 | 574402005445344 |
10 | 133433043222019 |
11 | 395746aa341052 |
12 | 12b70274245057 |
13 | 595b8b3423ca8 |
14 | 24d429d91a559 |
15 | 1065d76590364 |
hex | 795b4d247e03 |
133433043222019 has 2 divisors, whose sum is σ = 133433043222020. Its totient is φ = 133433043222018.
The previous prime is 133433043221941. The next prime is 133433043222097. The reversal of 133433043222019 is 910222340334331.
It is a balanced prime because it is at equal distance from previous prime (133433043221941) and next prime (133433043222097).
It is a cyclic number.
It is not a de Polignac number, because 133433043222019 - 245 = 98248671133187 is a prime.
It is a super-2 number, since 2×1334330432220192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133433043228019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66716521611009 + 66716521611010.
It is an arithmetic number, because the mean of its divisors is an integer number (66716521611010).
Almost surely, 2133433043222019 is an apocalyptic number.
133433043222019 is a deficient number, since it is larger than the sum of its proper divisors (1).
133433043222019 is an equidigital number, since it uses as much as digits as its factorization.
133433043222019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 40.
The spelling of 133433043222019 in words is "one hundred thirty-three trillion, four hundred thirty-three billion, forty-three million, two hundred twenty-two thousand, nineteen".
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