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133433201403121 is a prime number
BaseRepresentation
bin11110010101101101010110…
…100100100010010011110001
3122111110002102020010222001211
4132111231112210202103301
5114442132144024344441
61151442211055000121
740051142056141324
oct3625552644422361
9574402366128054
10133433201403121
1139574780660934
1212b702b9209041
13595b90a128889
1424d42b69347bb
151065d853d8a81
hex795b569224f1

133433201403121 has 2 divisors, whose sum is σ = 133433201403122. Its totient is φ = 133433201403120.

The previous prime is 133433201403119. The next prime is 133433201403137. The reversal of 133433201403121 is 121304102334331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70034804942400 + 63398396460721 = 8368680^2 + 7962311^2 .

It is a cyclic number.

It is not a de Polignac number, because 133433201403121 - 21 = 133433201403119 is a prime.

Together with 133433201403119, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (133433201403221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66716600701560 + 66716600701561.

It is an arithmetic number, because the mean of its divisors is an integer number (66716600701561).

Almost surely, 2133433201403121 is an apocalyptic number.

It is an amenable number.

133433201403121 is a deficient number, since it is larger than the sum of its proper divisors (1).

133433201403121 is an equidigital number, since it uses as much as digits as its factorization.

133433201403121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 133433201403121 its reverse (121304102334331), we get a palindrome (254737303737452).

The spelling of 133433201403121 in words is "one hundred thirty-three trillion, four hundred thirty-three billion, two hundred one million, four hundred three thousand, one hundred twenty-one".