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133434021121 is a prime number
BaseRepresentation
bin111110001000101001…
…0011001010100000001
3110202102020122121000021
41330101102121110001
54141233102133441
6141144310053441
712432422315512
oct1742122312401
9422366577007
10133434021121
1151653032015
1221a3a94a281
13c77647c9ab
14665b5b0a09
15370e58b3d1
hex1f11499501

133434021121 has 2 divisors, whose sum is σ = 133434021122. Its totient is φ = 133434021120.

The previous prime is 133434021103. The next prime is 133434021131. The reversal of 133434021121 is 121120434331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101190791025 + 32243230096 = 318105^2 + 179564^2 .

It is a cyclic number.

It is not a de Polignac number, because 133434021121 - 29 = 133434020609 is a prime.

It is a super-3 number, since 3×1334340211213 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (133434021131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66717010560 + 66717010561.

It is an arithmetic number, because the mean of its divisors is an integer number (66717010561).

Almost surely, 2133434021121 is an apocalyptic number.

It is an amenable number.

133434021121 is a deficient number, since it is larger than the sum of its proper divisors (1).

133434021121 is an equidigital number, since it uses as much as digits as its factorization.

133434021121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 133434021121 its reverse (121120434331), we get a palindrome (254554455452).

The spelling of 133434021121 in words is "one hundred thirty-three billion, four hundred thirty-four million, twenty-one thousand, one hundred twenty-one".