Base | Representation |
---|---|
bin | 11000110110101111… |
… | …10001110110010110 |
3 | 1021102222022112122121 |
4 | 30123113301312112 |
5 | 204312043321324 |
6 | 10044042450154 |
7 | 651452102365 |
oct | 143327616626 |
9 | 37388275577 |
10 | 13344120214 |
11 | 5728454027 |
12 | 2704b0395a |
13 | 1348779829 |
14 | 9083457dc |
15 | 5317785e4 |
hex | 31b5f1d96 |
13344120214 has 4 divisors (see below), whose sum is σ = 20016180324. Its totient is φ = 6672060106.
The previous prime is 13344120193. The next prime is 13344120311. The reversal of 13344120214 is 41202144331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41202144331 = 7237 ⋅5693263.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3336030052 + ... + 3336030055.
It is an arithmetic number, because the mean of its divisors is an integer number (5004045081).
Almost surely, 213344120214 is an apocalyptic number.
13344120214 is a deficient number, since it is larger than the sum of its proper divisors (6672060110).
13344120214 is an equidigital number, since it uses as much as digits as its factorization.
13344120214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6672060109.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13344120214 its reverse (41202144331), we get a palindrome (54546264545).
The spelling of 13344120214 in words is "thirteen billion, three hundred forty-four million, one hundred twenty thousand, two hundred fourteen".
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