Base | Representation |
---|---|
bin | 100111110001001… |
… | …1000101100011111 |
3 | 10102222221021000212 |
4 | 1033202120230133 |
5 | 10213102222421 |
6 | 340225043035 |
7 | 45032222102 |
oct | 11742305437 |
9 | 3388837025 |
10 | 1334414111 |
11 | 625273088 |
12 | 312a8647b |
13 | 1835c7164 |
14 | c931c739 |
15 | 7c23be5b |
hex | 4f898b1f |
1334414111 has 2 divisors, whose sum is σ = 1334414112. Its totient is φ = 1334414110.
The previous prime is 1334414089. The next prime is 1334414117. The reversal of 1334414111 is 1114144331.
It is a strong prime.
It is an emirp because it is prime and its reverse (1114144331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1334414111 - 218 = 1334151967 is a prime.
It is a super-2 number, since 2×13344141112 = 3561322039271840642, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1334414117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667207055 + 667207056.
It is an arithmetic number, because the mean of its divisors is an integer number (667207056).
Almost surely, 21334414111 is an apocalyptic number.
1334414111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334414111 is an equidigital number, since it uses as much as digits as its factorization.
1334414111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 576, while the sum is 23.
The square root of 1334414111 is about 36529.6333269306. The cubic root of 1334414111 is about 1100.9397234176.
Adding to 1334414111 its reverse (1114144331), we get a palindrome (2448558442).
The spelling of 1334414111 in words is "one billion, three hundred thirty-four million, four hundred fourteen thousand, one hundred eleven".
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