Base | Representation |
---|---|
bin | 1111111010000… |
… | …10111011100101 |
3 | 100022002121210111 |
4 | 13331002323211 |
5 | 233130141201 |
6 | 21124053021 |
7 | 3210151345 |
oct | 775027345 |
9 | 308077714 |
10 | 133443301 |
11 | 69363a22 |
12 | 38834171 |
13 | 21852b44 |
14 | 13a18d25 |
15 | baadb51 |
hex | 7f42ee5 |
133443301 has 4 divisors (see below), whose sum is σ = 133605100. Its totient is φ = 133281504.
The previous prime is 133443287. The next prime is 133443311. The reversal of 133443301 is 103344331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 49702500 + 83740801 = 7050^2 + 9151^2 .
It is a cyclic number.
It is not a de Polignac number, because 133443301 - 29 = 133442789 is a prime.
It is a super-2 number, since 2×1334433012 = 35614229163553202, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133443311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79656 + ... + 81313.
It is an arithmetic number, because the mean of its divisors is an integer number (33401275).
Almost surely, 2133443301 is an apocalyptic number.
It is an amenable number.
133443301 is a deficient number, since it is larger than the sum of its proper divisors (161799).
133443301 is an equidigital number, since it uses as much as digits as its factorization.
133443301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161798.
The product of its (nonzero) digits is 1296, while the sum is 22.
The square root of 133443301 is about 11551.7661420235. The cubic root of 133443301 is about 511.0133651017.
Adding to 133443301 its reverse (103344331), we get a palindrome (236787632).
It can be divided in two parts, 13344330 and 1, that added together give a palindrome (13344331).
The spelling of 133443301 in words is "one hundred thirty-three million, four hundred forty-three thousand, three hundred one".
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