Base | Representation |
---|---|
bin | 11110010110000001110000… |
… | …000100110001110010010011 |
3 | 122111112011221122222100221021 |
4 | 132112001300010301302103 |
5 | 114443012023123401003 |
6 | 1151500232314140311 |
7 | 40052545614160516 |
oct | 3626016004616223 |
9 | 574464848870837 |
10 | 133455104122003 |
11 | 39582aa01227a4 |
12 | 12b745b0421697 |
13 | 59609baa79771 |
14 | 24d53937d0d7d |
15 | 10667181ed2bd |
hex | 796070131c93 |
133455104122003 has 2 divisors, whose sum is σ = 133455104122004. Its totient is φ = 133455104122002.
The previous prime is 133455104121971. The next prime is 133455104122033. The reversal of 133455104122003 is 300221401554331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133455104122003 - 25 = 133455104121971 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133455104122003.
It is not a weakly prime, because it can be changed into another prime (133455104122033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66727552061001 + 66727552061002.
It is an arithmetic number, because the mean of its divisors is an integer number (66727552061002).
Almost surely, 2133455104122003 is an apocalyptic number.
133455104122003 is a deficient number, since it is larger than the sum of its proper divisors (1).
133455104122003 is an equidigital number, since it uses as much as digits as its factorization.
133455104122003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 133455104122003 its reverse (300221401554331), we get a palindrome (433676505676334).
The spelling of 133455104122003 in words is "one hundred thirty-three trillion, four hundred fifty-five billion, one hundred four million, one hundred twenty-two thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •