Base | Representation |
---|---|
bin | 11110010110000110010101… |
… | …010000111001011100101000 |
3 | 122111112122122110202110010111 |
4 | 132112012111100321130220 |
5 | 114443102111343222100 |
6 | 1151502404351224104 |
7 | 40053111533145103 |
oct | 3626062520713450 |
9 | 574478573673114 |
10 | 133460023023400 |
11 | 39585094779167 |
12 | 12b75543818034 |
13 | 59612c2b81bc8 |
14 | 24d56dcbc173a |
15 | 1066904e856ba |
hex | 796195439728 |
133460023023400 has 48 divisors (see below), whose sum is σ = 310644378692640. Its totient is φ = 53323824235200.
The previous prime is 133460023023277. The next prime is 133460023023407. The reversal of 133460023023400 is 4320320064331.
It is not an unprimeable number, because it can be changed into a prime (133460023023407) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 375978246 + ... + 376333045.
It is an arithmetic number, because the mean of its divisors is an integer number (6471757889430).
Almost surely, 2133460023023400 is an apocalyptic number.
133460023023400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133460023023400 is an abundant number, since it is smaller than the sum of its proper divisors (177184355669240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133460023023400 is a wasteful number, since it uses less digits than its factorization.
133460023023400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 752312194 (or 752312185 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 133460023023400 its reverse (4320320064331), we get a palindrome (137780343087731).
The spelling of 133460023023400 in words is "one hundred thirty-three trillion, four hundred sixty billion, twenty-three million, twenty-three thousand, four hundred".
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