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133462025240539 is a prime number
BaseRepresentation
bin11110010110001000001100…
…100110101111111111011011
3122111112211211000021121200211
4132112020030212233333123
5114443120211430144124
61151503335153511551
740053212254542622
oct3626101446577733
9574484730247624
10133462025240539
1139585a2199a576
1212b75a022725b7
135961551924488
1424d584ca966b9
1510669c0b34e94
hex79620c9affdb

133462025240539 has 2 divisors, whose sum is σ = 133462025240540. Its totient is φ = 133462025240538.

The previous prime is 133462025240393. The next prime is 133462025240563. The reversal of 133462025240539 is 935042520264331.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133462025240539 is a prime.

It is a super-2 number, since 2×1334620252405392 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133462025240492 and 133462025240501.

It is not a weakly prime, because it can be changed into another prime (133462025220539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66731012620269 + 66731012620270.

It is an arithmetic number, because the mean of its divisors is an integer number (66731012620270).

Almost surely, 2133462025240539 is an apocalyptic number.

133462025240539 is a deficient number, since it is larger than the sum of its proper divisors (1).

133462025240539 is an equidigital number, since it uses as much as digits as its factorization.

133462025240539 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4665600, while the sum is 49.

The spelling of 133462025240539 in words is "one hundred thirty-three trillion, four hundred sixty-two billion, twenty-five million, two hundred forty thousand, five hundred thirty-nine".