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133466801320001 is a prime number
BaseRepresentation
bin11110010110001100101001…
…010010000011000001000001
3122111120022010212022121000202
4132112030221102003001001
5114443210002114220001
61151505445125454545
740053441520544552
oct3626145122030101
9574508125277022
10133466801320001
1139587a52966786
1212b76915871455
135961b33271cb6
1424d5b8310a329
151066ba00a996b
hex796329483041

133466801320001 has 2 divisors, whose sum is σ = 133466801320002. Its totient is φ = 133466801320000.

The previous prime is 133466801319953. The next prime is 133466801320091. The reversal of 133466801320001 is 100023108664331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133386884856976 + 79916463025 = 11549324^2 + 282695^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133466801320001 is a prime.

It is a super-3 number, since 3×1334668013200013 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (133466801320091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66733400660000 + 66733400660001.

It is an arithmetic number, because the mean of its divisors is an integer number (66733400660001).

Almost surely, 2133466801320001 is an apocalyptic number.

It is an amenable number.

133466801320001 is a deficient number, since it is larger than the sum of its proper divisors (1).

133466801320001 is an equidigital number, since it uses as much as digits as its factorization.

133466801320001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 38.

Adding to 133466801320001 its reverse (100023108664331), we get a palindrome (233489909984332).

The spelling of 133466801320001 in words is "one hundred thirty-three trillion, four hundred sixty-six billion, eight hundred one million, three hundred twenty thousand, one".