Base | Representation |
---|---|
bin | 111110001001110010… |
… | …0010001101101011011 |
3 | 110202111220121111000021 |
4 | 1330103210101231123 |
5 | 4141322344404003 |
6 | 141152153451311 |
7 | 12433365342052 |
oct | 1742344215533 |
9 | 422456544007 |
10 | 133472263003 |
11 | 51672681782 |
12 | 21a4b710b37 |
13 | c78137c221 |
14 | 66626c7399 |
15 | 3712ae22bd |
hex | 1f13911b5b |
133472263003 has 2 divisors, whose sum is σ = 133472263004. Its totient is φ = 133472263002.
The previous prime is 133472262961. The next prime is 133472263019. The reversal of 133472263003 is 300362274331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133472263003 is a prime.
It is a super-3 number, since 3×1334722630033 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 133472263003.
It is not a weakly prime, because it can be changed into another prime (133472263103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66736131501 + 66736131502.
It is an arithmetic number, because the mean of its divisors is an integer number (66736131502).
Almost surely, 2133472263003 is an apocalyptic number.
133472263003 is a deficient number, since it is larger than the sum of its proper divisors (1).
133472263003 is an equidigital number, since it uses as much as digits as its factorization.
133472263003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 34.
The spelling of 133472263003 in words is "one hundred thirty-three billion, four hundred seventy-two million, two hundred sixty-three thousand, three".
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