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133473405137 is a prime number
BaseRepresentation
bin111110001001110100…
…0101000100011010001
3110202111222202111201112
41330103220220203101
54141323142431022
6141152234143105
712433411136642
oct1742350504321
9422458674645
10133473405137
1151673291896
1221a4bb81a95
13c78168c047
1466629036c9
153712c6a8e2
hex1f13a288d1

133473405137 has 2 divisors, whose sum is σ = 133473405138. Its totient is φ = 133473405136.

The previous prime is 133473405133. The next prime is 133473405179. The reversal of 133473405137 is 731504374331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81839477776 + 51633927361 = 286076^2 + 227231^2 .

It is a cyclic number.

It is not a de Polignac number, because 133473405137 - 22 = 133473405133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133473405094 and 133473405103.

It is not a weakly prime, because it can be changed into another prime (133473405133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66736702568 + 66736702569.

It is an arithmetic number, because the mean of its divisors is an integer number (66736702569).

Almost surely, 2133473405137 is an apocalyptic number.

It is an amenable number.

133473405137 is a deficient number, since it is larger than the sum of its proper divisors (1).

133473405137 is an equidigital number, since it uses as much as digits as its factorization.

133473405137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 317520, while the sum is 41.

Adding to 133473405137 its reverse (731504374331), we get a palindrome (864977779468).

The spelling of 133473405137 in words is "one hundred thirty-three billion, four hundred seventy-three million, four hundred five thousand, one hundred thirty-seven".