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13347664809341 is a prime number
BaseRepresentation
bin1100001000111011111011…
…0100011100110101111101
31202021000122201011202021112
43002032332310130311331
53222142004142344331
644215455500011405
72545223401620542
oct302167664346575
952230581152245
1013347664809341
1142867928a2805
1215b6a49b30b65
1375a8aa810105
1434205d6a8bc9
1518230b6b732b
hexc23bed1cd7d

13347664809341 has 2 divisors, whose sum is σ = 13347664809342. Its totient is φ = 13347664809340.

The previous prime is 13347664809299. The next prime is 13347664809419. The reversal of 13347664809341 is 14390846674331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9721892820025 + 3625771989316 = 3117995^2 + 1904146^2 .

It is a cyclic number.

It is not a de Polignac number, because 13347664809341 - 218 = 13347664547197 is a prime.

It is a super-2 number, since 2×133476648093412 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13347664809541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6673832404670 + 6673832404671.

It is an arithmetic number, because the mean of its divisors is an integer number (6673832404671).

Almost surely, 213347664809341 is an apocalyptic number.

It is an amenable number.

13347664809341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13347664809341 is an equidigital number, since it uses as much as digits as its factorization.

13347664809341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31352832, while the sum is 59.

The spelling of 13347664809341 in words is "thirteen trillion, three hundred forty-seven billion, six hundred sixty-four million, eight hundred nine thousand, three hundred forty-one".