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133501233302323 is a prime number
BaseRepresentation
bin11110010110101100101101…
…100101101000101100110011
3122111200121000111011112012021
4132112230231211220230303
5114444241011211133243
61151533341522412311
740056101004554635
oct3626545545505463
9574617014145167
10133501233302323
11395a0611913717
1212b81524b01097
13596515c8b7433
1424d76cbdd6a55
151067a17d386ed
hex796b2d968b33

133501233302323 has 2 divisors, whose sum is σ = 133501233302324. Its totient is φ = 133501233302322.

The previous prime is 133501233302233. The next prime is 133501233302429. The reversal of 133501233302323 is 323203332105331.

Together with previous prime (133501233302233) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (323203332105331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133501233302323 - 233 = 133492643367731 is a prime.

It is not a weakly prime, because it can be changed into another prime (133501233362323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66750616651161 + 66750616651162.

It is an arithmetic number, because the mean of its divisors is an integer number (66750616651162).

Almost surely, 2133501233302323 is an apocalyptic number.

133501233302323 is a deficient number, since it is larger than the sum of its proper divisors (1).

133501233302323 is an equidigital number, since it uses as much as digits as its factorization.

133501233302323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 87480, while the sum is 34.

Adding to 133501233302323 its reverse (323203332105331), we get a palindrome (456704565407654).

The spelling of 133501233302323 in words is "one hundred thirty-three trillion, five hundred one billion, two hundred thirty-three million, three hundred two thousand, three hundred twenty-three".