1335100147 has 2 divisors, whose sum is σ = 1335100148. Its totient is φ = 1335100146.

The previous prime is 1335100121. The next prime is 1335100181. The reversal of 1335100147 is 7410015331.

It is a weak prime.

It is an emirp because it is prime and its reverse (7410015331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1335100147 is a prime.

It is not a weakly prime, because it can be changed into another prime (1335400147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667550073 + 667550074.

It is an arithmetic number, because the mean of its divisors is an integer number (667550074).

Almost surely, 2^1335100147 is an apocalyptic number.

1335100147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1335100147 is an equidigital number, since it uses as much as digits as its factorization.

1335100147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 25.

The square root of 1335100147 is about 36539.0222501916. The cubic root of 1335100147 is about 1101.1283592345.

Adding to 1335100147 its reverse (7410015331), we get a palindrome (8745115478).

The spelling of 1335100147 in words is "one billion, three hundred thirty-five million, one hundred thousand, one hundred forty-seven".