Base | Representation |
---|---|
bin | 11000110111100101… |
… | …00100101001001110 |
3 | 1021110110112101111100 |
4 | 30123302210221032 |
5 | 204320343102024 |
6 | 10044453203530 |
7 | 651565565055 |
oct | 143362445116 |
9 | 37413471440 |
10 | 13351144014 |
11 | 573141111a |
12 | 27073305a6 |
13 | 134a068820 |
14 | 90925339c |
15 | 5321b47c9 |
hex | 31bca4a4e |
13351144014 has 24 divisors (see below), whose sum is σ = 31152669912. Its totient is φ = 4108044240.
The previous prime is 13351144007. The next prime is 13351144061. The reversal of 13351144014 is 41044115331.
13351144014 is a `hidden beast` number, since 133 + 511 + 4 + 4 + 0 + 14 = 666.
13351144014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 28527852 + ... + 28528319.
It is an arithmetic number, because the mean of its divisors is an integer number (1298027913).
Almost surely, 213351144014 is an apocalyptic number.
13351144014 is an abundant number, since it is smaller than the sum of its proper divisors (17801525898).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13351144014 is a wasteful number, since it uses less digits than its factorization.
13351144014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57056192 (or 57056189 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 13351144014 its reverse (41044115331), we get a palindrome (54395259345).
The spelling of 13351144014 in words is "thirteen billion, three hundred fifty-one million, one hundred forty-four thousand, fourteen".
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