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133512612686249 is a prime number
BaseRepresentation
bin11110010110110111010011…
…110110100010100110101001
3122111201200101112111010100012
4132112313103312202212221
5114444432312321424444
61151542503022221305
740056653001666236
oct3626672366424651
9574650345433305
10133512612686249
11395a5421216245
1212b8377ba24835
1359662542b56c4
1424d808b42278d
151067e81d67b9e
hex796dd3da29a9

133512612686249 has 2 divisors, whose sum is σ = 133512612686250. Its totient is φ = 133512612686248.

The previous prime is 133512612686221. The next prime is 133512612686251. The reversal of 133512612686249 is 942686216215331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102192527977024 + 31320084709225 = 10109032^2 + 5596435^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133512612686249 is a prime.

Together with 133512612686251, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133512612686149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66756306343124 + 66756306343125.

It is an arithmetic number, because the mean of its divisors is an integer number (66756306343125).

Almost surely, 2133512612686249 is an apocalyptic number.

It is an amenable number.

133512612686249 is a deficient number, since it is larger than the sum of its proper divisors (1).

133512612686249 is an equidigital number, since it uses as much as digits as its factorization.

133512612686249 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 22394880, while the sum is 59.

The spelling of 133512612686249 in words is "one hundred thirty-three trillion, five hundred twelve billion, six hundred twelve million, six hundred eighty-six thousand, two hundred forty-nine".