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1335134131 is a prime number
BaseRepresentation
bin100111110010100…
…1000011110110011
310110001021211201021
41033211020132303
510213243243011
6340252320311
745041311222
oct11745103663
93401254637
101335134131
11625715041
12313173097
131837b9ac6
14c9468cb9
157c330471
hex4f9487b3

1335134131 has 2 divisors, whose sum is σ = 1335134132. Its totient is φ = 1335134130.

The previous prime is 1335134113. The next prime is 1335134147. The reversal of 1335134131 is 1314315331.

Together with previous prime (1335134113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1335134131 - 29 = 1335133619 is a prime.

It is a super-2 number, since 2×13351341312 = 3565166295522250322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1335134096 and 1335134105.

It is not a weakly prime, because it can be changed into another prime (1335134191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667567065 + 667567066.

It is an arithmetic number, because the mean of its divisors is an integer number (667567066).

Almost surely, 21335134131 is an apocalyptic number.

1335134131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1335134131 is an equidigital number, since it uses as much as digits as its factorization.

1335134131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1620, while the sum is 25.

The square root of 1335134131 is about 36539.4872843065. The cubic root of 1335134131 is about 1101.1377019615.

Adding to 1335134131 its reverse (1314315331), we get a palindrome (2649449462).

The spelling of 1335134131 in words is "one billion, three hundred thirty-five million, one hundred thirty-four thousand, one hundred thirty-one".