Base | Representation |
---|---|
bin | 1100001001001010000011… |
… | …0000001011111000010111 |
3 | 1202021101102212201202200211 |
4 | 3002102200300023320113 |
5 | 3222222240031421403 |
6 | 44221323544150251 |
7 | 2545416336616504 |
oct | 302224060137027 |
9 | 52241385652624 |
10 | 13351455342103 |
11 | 428835851810a |
12 | 15b7727468387 |
13 | 75b062c112c8 |
14 | 3422dcc944ab |
15 | 18247e36306d |
hex | c24a0c0be17 |
13351455342103 has 2 divisors, whose sum is σ = 13351455342104. Its totient is φ = 13351455342102.
The previous prime is 13351455342083. The next prime is 13351455342133. The reversal of 13351455342103 is 30124355415331.
It is a weak prime.
It is an emirp because it is prime and its reverse (30124355415331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13351455342103 is a prime.
It is a super-2 number, since 2×133514553421032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13351455342133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675727671051 + 6675727671052.
It is an arithmetic number, because the mean of its divisors is an integer number (6675727671052).
Almost surely, 213351455342103 is an apocalyptic number.
13351455342103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13351455342103 is an equidigital number, since it uses as much as digits as its factorization.
13351455342103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 40.
The spelling of 13351455342103 in words is "thirteen trillion, three hundred fifty-one billion, four hundred fifty-five million, three hundred forty-two thousand, one hundred three".
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