Base | Representation |
---|---|
bin | 1100001001001010001110… |
… | …0000011011001010011111 |
3 | 1202021101120002122222002212 |
4 | 3002102203200123022133 |
5 | 3222222333343321142 |
6 | 44221332314311035 |
7 | 2545420440406304 |
oct | 302224340331237 |
9 | 52241502588085 |
10 | 13351501542047 |
11 | 4288381602889 |
12 | 15b773aa2847b |
13 | 75b06c668b56 |
14 | 34230507d0ab |
15 | 18248343bd82 |
hex | c24a381b29f |
13351501542047 has 2 divisors, whose sum is σ = 13351501542048. Its totient is φ = 13351501542046.
The previous prime is 13351501542037. The next prime is 13351501542053. The reversal of 13351501542047 is 74024510515331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13351501542047 - 218 = 13351501279903 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13351501541995 and 13351501542013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13351501542037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675750771023 + 6675750771024.
It is an arithmetic number, because the mean of its divisors is an integer number (6675750771024).
Almost surely, 213351501542047 is an apocalyptic number.
13351501542047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13351501542047 is an equidigital number, since it uses as much as digits as its factorization.
13351501542047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252000, while the sum is 41.
The spelling of 13351501542047 in words is "thirteen trillion, three hundred fifty-one billion, five hundred one million, five hundred forty-two thousand, forty-seven".
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