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13352003520255 = 3252312900486493
BaseRepresentation
bin1100001001001100000101…
…1011010100011011111111
31202021102212002020002202100
43002103001123110123333
53222224400400122010
644221454205400143
72545436044222521
oct302230133243377
952242762202670
1013352003520255
1142886099a0504
1215b785ab69053
1375b11c66448a
143423519cba11
151824b25462c0
hexc24c16d46ff

13352003520255 has 24 divisors (see below), whose sum is σ = 24149710716768. Its totient is φ = 6811456867776.

The previous prime is 13352003520253. The next prime is 13352003520257. The reversal of 13352003520255 is 55202530025331.

13352003520255 is a `hidden beast` number, since 1 + 3 + 3 + 52 + 0 + 0 + 352 + 0 + 255 = 666.

It is an interprime number because it is at equal distance from previous prime (13352003520253) and next prime (13352003520257).

It is not a de Polignac number, because 13352003520255 - 21 = 13352003520253 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13352003520253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6450242212 + ... + 6450244281.

It is an arithmetic number, because the mean of its divisors is an integer number (1006237946532).

Almost surely, 213352003520255 is an apocalyptic number.

13352003520255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13352003520255 is a deficient number, since it is larger than the sum of its proper divisors (10797707196513).

13352003520255 is a wasteful number, since it uses less digits than its factorization.

13352003520255 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12900486527 (or 12900486524 counting only the distinct ones).

The product of its (nonzero) digits is 135000, while the sum is 36.

Adding to 13352003520255 its reverse (55202530025331), we get a palindrome (68554533545586).

The spelling of 13352003520255 in words is "thirteen trillion, three hundred fifty-two billion, three million, five hundred twenty thousand, two hundred fifty-five".

Divisors: 1 3 5 9 15 23 45 69 115 207 345 1035 12900486493 38701459479 64502432465 116104378437 193507297395 296711189339 580521892185 890133568017 1483555946695 2670400704051 4450667840085 13352003520255