13352100403501 has 4 divisors (see below), whose sum is σ = 13712967982012. Its totient is φ = 12991232824992.

The previous prime is 13352100403487. The next prime is 13352100403507. The reversal of 13352100403501 is 10530400125331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7024355122500 + 6327745281001 = 2650350^2 + 2515501^2 .

It is a cyclic number.

It is not a de Polignac number, because 13352100403501 - 2¹⁵ = 13352100370733 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13352100403501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13352100403507) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180433789200 + ... + 180433789273.

It is an arithmetic number, because the mean of its divisors is an integer number (3428241995503).

Almost surely, 2^{13352100403501} is an apocalyptic number.

It is an amenable number.

13352100403501 is a deficient number, since it is larger than the sum of its proper divisors (360867578511).

13352100403501 is an equidigital number, since it uses as much as digits as its factorization.

13352100403501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 360867578510.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 13352100403501 its reverse (10530400125331), we get a palindrome (23882500528832).

The spelling of 13352100403501 in words is "thirteen trillion, three hundred fifty-two billion, one hundred million, four hundred three thousand, five hundred one".