Base | Representation |
---|---|
bin | 1100001001001100011100… |
… | …1100111001100100110011 |
3 | 1202021110002211112021120221 |
4 | 3002103013030321210303 |
5 | 3222230100200403012 |
6 | 44221511550113511 |
7 | 2545441331554135 |
oct | 302230714714463 |
9 | 52243084467527 |
10 | 13352100403507 |
11 | 4288659653308 |
12 | 15b78874ab897 |
13 | 75b136756448 |
14 | 34236080b055 |
15 | 1824bacd2507 |
hex | c24c7339933 |
13352100403507 has 2 divisors, whose sum is σ = 13352100403508. Its totient is φ = 13352100403506.
The previous prime is 13352100403487. The next prime is 13352100403511. The reversal of 13352100403507 is 70530400125331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13352100403507 is a prime.
It is not a weakly prime, because it can be changed into another prime (13352100403517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676050201753 + 6676050201754.
It is an arithmetic number, because the mean of its divisors is an integer number (6676050201754).
Almost surely, 213352100403507 is an apocalyptic number.
13352100403507 is a deficient number, since it is larger than the sum of its proper divisors (1).
13352100403507 is an equidigital number, since it uses as much as digits as its factorization.
13352100403507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 37800, while the sum is 34.
Adding to 13352100403507 its reverse (70530400125331), we get a palindrome (83882500528838).
The spelling of 13352100403507 in words is "thirteen trillion, three hundred fifty-two billion, one hundred million, four hundred three thousand, five hundred seven".
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