Base | Representation |
---|---|
bin | 1100001001001101110000… |
… | …1111100100000101000111 |
3 | 1202021111000102210112212221 |
4 | 3002103130033210011013 |
5 | 3222231311034022211 |
6 | 44222011000353211 |
7 | 2545453146306553 |
oct | 302233417440507 |
9 | 52244012715787 |
10 | 13352453423431 |
11 | 428881a950411 |
12 | 15b7965775807 |
13 | 75b191929085 |
14 | 342395662863 |
15 | 1824dbcb5c71 |
hex | c24dc3e4147 |
13352453423431 has 2 divisors, whose sum is σ = 13352453423432. Its totient is φ = 13352453423430.
The previous prime is 13352453423399. The next prime is 13352453423483. The reversal of 13352453423431 is 13432435425331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13352453423431 - 25 = 13352453423399 is a prime.
It is a super-2 number, since 2×133524534234312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13352454423431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676226711715 + 6676226711716.
It is an arithmetic number, because the mean of its divisors is an integer number (6676226711716).
Almost surely, 213352453423431 is an apocalyptic number.
13352453423431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13352453423431 is an equidigital number, since it uses as much as digits as its factorization.
13352453423431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1555200, while the sum is 43.
Adding to 13352453423431 its reverse (13432435425331), we get a palindrome (26784888848762).
The spelling of 13352453423431 in words is "thirteen trillion, three hundred fifty-two billion, four hundred fifty-three million, four hundred twenty-three thousand, four hundred thirty-one".
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