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13352524500493 is a prime number
BaseRepresentation
bin1100001001001110000001…
…1110101100111000001101
31202021111012101112122021201
43002103200132230320031
53222231432233003433
644222022020025501
72545455001410403
oct302234036547015
952244171478251
1013352524500493
114288856a87692
1215b7985532291
1375b1a3583bc9
143423a0c85473
151824e3155a7d
hexc24e07ace0d

13352524500493 has 2 divisors, whose sum is σ = 13352524500494. Its totient is φ = 13352524500492.

The previous prime is 13352524500487. The next prime is 13352524500587. The reversal of 13352524500493 is 39400542525331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8000876130724 + 5351648369769 = 2828582^2 + 2313363^2 .

It is a cyclic number.

It is not a de Polignac number, because 13352524500493 - 29 = 13352524499981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13352524500463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676262250246 + 6676262250247.

It is an arithmetic number, because the mean of its divisors is an integer number (6676262250247).

Almost surely, 213352524500493 is an apocalyptic number.

It is an amenable number.

13352524500493 is a deficient number, since it is larger than the sum of its proper divisors (1).

13352524500493 is an equidigital number, since it uses as much as digits as its factorization.

13352524500493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944000, while the sum is 46.

The spelling of 13352524500493 in words is "thirteen trillion, three hundred fifty-two billion, five hundred twenty-four million, five hundred thousand, four hundred ninety-three".