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13352525087333 is a prime number
BaseRepresentation
bin1100001001001110000010…
…0000111100001001100101
31202021111012102122110021112
43002103200200330021211
53222231432410243313
644222022040354405
72545455006403325
oct302234040741145
952244172573245
1013352525087333
114288857348583
1215b7985775a05
1375b1a372b053
143423a0d99285
151824e321e8a8
hexc24e083c265

13352525087333 has 2 divisors, whose sum is σ = 13352525087334. Its totient is φ = 13352525087332.

The previous prime is 13352525087323. The next prime is 13352525087411. The reversal of 13352525087333 is 33378052525331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9804150420964 + 3548374666369 = 3131158^2 + 1883713^2 .

It is a cyclic number.

It is not a de Polignac number, because 13352525087333 - 214 = 13352525070949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13352525087323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676262543666 + 6676262543667.

It is an arithmetic number, because the mean of its divisors is an integer number (6676262543667).

Almost surely, 213352525087333 is an apocalyptic number.

It is an amenable number.

13352525087333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13352525087333 is an equidigital number, since it uses as much as digits as its factorization.

13352525087333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804000, while the sum is 50.

The spelling of 13352525087333 in words is "thirteen trillion, three hundred fifty-two billion, five hundred twenty-five million, eighty-seven thousand, three hundred thirty-three".