Base | Representation |
---|---|
bin | 1100001001001110000010… |
… | …0010101101100110100111 |
3 | 1202021111012110112001201212 |
4 | 3002103200202231212213 |
5 | 3222231433020131124 |
6 | 44222022054342035 |
7 | 2545455013350212 |
oct | 302234042554647 |
9 | 52244173461655 |
10 | 13352525552039 |
11 | 4288857635733 |
12 | 15b798595a91b |
13 | 75b1a386171b |
14 | 3423a107a779 |
15 | 1824e32b240e |
hex | c24e08ad9a7 |
13352525552039 has 2 divisors, whose sum is σ = 13352525552040. Its totient is φ = 13352525552038.
The previous prime is 13352525552033. The next prime is 13352525552053. The reversal of 13352525552039 is 93025552525331.
It is a weak prime.
It is an emirp because it is prime and its reverse (93025552525331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13352525552039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13352525552033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676262776019 + 6676262776020.
It is an arithmetic number, because the mean of its divisors is an integer number (6676262776020).
Almost surely, 213352525552039 is an apocalyptic number.
13352525552039 is a deficient number, since it is larger than the sum of its proper divisors (1).
13352525552039 is an equidigital number, since it uses as much as digits as its factorization.
13352525552039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6075000, while the sum is 50.
The spelling of 13352525552039 in words is "thirteen trillion, three hundred fifty-two billion, five hundred twenty-five million, five hundred fifty-two thousand, thirty-nine".
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