Base | Representation |
---|---|
bin | 111110001011010111… |
… | …0011111010111010011 |
3 | 110202122121100121201011 |
4 | 1330112232133113103 |
5 | 4141424432201034 |
6 | 141201325551351 |
7 | 12434611041226 |
oct | 1742656372723 |
9 | 422577317634 |
10 | 133525272019 |
11 | 5169a598187 |
12 | 21a65415557 |
13 | c78c34c0c9 |
14 | 66697655bd |
15 | 37175b3864 |
hex | 1f16b9f5d3 |
133525272019 has 2 divisors, whose sum is σ = 133525272020. Its totient is φ = 133525272018.
The previous prime is 133525272017. The next prime is 133525272031. The reversal of 133525272019 is 910272525331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133525272019 - 21 = 133525272017 is a prime.
It is a super-2 number, since 2×1335252720192 (a number of 23 digits) contains 22 as substring.
Together with 133525272017, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (133525272017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66762636009 + 66762636010.
It is an arithmetic number, because the mean of its divisors is an integer number (66762636010).
Almost surely, 2133525272019 is an apocalyptic number.
133525272019 is a deficient number, since it is larger than the sum of its proper divisors (1).
133525272019 is an equidigital number, since it uses as much as digits as its factorization.
133525272019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 40.
The spelling of 133525272019 in words is "one hundred thirty-three billion, five hundred twenty-five million, two hundred seventy-two thousand, nineteen".
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