13353131041 has 2 divisors, whose sum is σ = 13353131042. Its totient is φ = 13353131040.

The previous prime is 13353130909. The next prime is 13353131059. The reversal of 13353131041 is 14013135331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8873640000 + 4479491041 = 94200^2 + 66929^2 .

It is a cyclic number.

It is not a de Polignac number, because 13353131041 - 2⁹ = 13353130529 is a prime.

It is a super-2 number, since 2×13353131041² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13353130997 and 13353131015.

It is not a weakly prime, because it can be changed into another prime (13353131081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676565520 + 6676565521.

It is an arithmetic number, because the mean of its divisors is an integer number (6676565521).

Almost surely, 2^13353131041 is an apocalyptic number.

It is an amenable number.

13353131041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353131041 is an equidigital number, since it uses as much as digits as its factorization.

13353131041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 13353131041 its reverse (14013135331), we get a palindrome (27366266372).

The spelling of 13353131041 in words is "thirteen billion, three hundred fifty-three million, one hundred thirty-one thousand, forty-one".