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133531534440589 is a prime number
BaseRepresentation
bin11110010111001000111011…
…101011010011100010001101
3122111210111020020002211121111
4132113020323223103202031
5120000240040304044324
61151555312353132021
740061222622153625
oct3627107353234215
9574714206084544
10133531534440589
113960245103934a
1212b8738085a011
135967c7b48844c
1424d8d6442d885
1510686dd0e8794
hex79723bad388d

133531534440589 has 2 divisors, whose sum is σ = 133531534440590. Its totient is φ = 133531534440588.

The previous prime is 133531534440497. The next prime is 133531534440607. The reversal of 133531534440589 is 985044435135331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128896103910564 + 4635430530025 = 11353242^2 + 2153005^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133531534440589 is a prime.

It is a super-2 number, since 2×1335315344405892 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133531534440389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66765767220294 + 66765767220295.

It is an arithmetic number, because the mean of its divisors is an integer number (66765767220295).

Almost surely, 2133531534440589 is an apocalyptic number.

It is an amenable number.

133531534440589 is a deficient number, since it is larger than the sum of its proper divisors (1).

133531534440589 is an equidigital number, since it uses as much as digits as its factorization.

133531534440589 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656000, while the sum is 58.

The spelling of 133531534440589 in words is "one hundred thirty-three trillion, five hundred thirty-one billion, five hundred thirty-four million, four hundred forty thousand, five hundred eighty-nine".