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133533520313147 is a prime number
BaseRepresentation
bin11110010111001010110010…
…000010110011101100111011
3122111210200100121212121121222
4132113022302002303230323
5120000303122200010042
61152000241413222255
740061323054615553
oct3627126202635473
9574720317777558
10133533520313147
1139603280006839
1212b8783593198b
135968206a27376
1424d90b208c163
1510687a761a2d2
hex7972b20b3b3b

133533520313147 has 2 divisors, whose sum is σ = 133533520313148. Its totient is φ = 133533520313146.

The previous prime is 133533520313093. The next prime is 133533520313239. The reversal of 133533520313147 is 741313025335331.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133533520313147 - 218 = 133533520051003 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133533520313098 and 133533520313107.

It is not a weakly prime, because it can be changed into another prime (133533520303147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66766760156573 + 66766760156574.

It is an arithmetic number, because the mean of its divisors is an integer number (66766760156574).

Almost surely, 2133533520313147 is an apocalyptic number.

133533520313147 is a deficient number, since it is larger than the sum of its proper divisors (1).

133533520313147 is an equidigital number, since it uses as much as digits as its factorization.

133533520313147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1020600, while the sum is 44.

Adding to 133533520313147 its reverse (741313025335331), we get a palindrome (874846545648478).

The spelling of 133533520313147 in words is "one hundred thirty-three trillion, five hundred thirty-three billion, five hundred twenty million, three hundred thirteen thousand, one hundred forty-seven".