Base | Representation |
---|---|
bin | 11110010111001010110010… |
… | …000010110011101100111011 |
3 | 122111210200100121212121121222 |
4 | 132113022302002303230323 |
5 | 120000303122200010042 |
6 | 1152000241413222255 |
7 | 40061323054615553 |
oct | 3627126202635473 |
9 | 574720317777558 |
10 | 133533520313147 |
11 | 39603280006839 |
12 | 12b8783593198b |
13 | 5968206a27376 |
14 | 24d90b208c163 |
15 | 10687a761a2d2 |
hex | 7972b20b3b3b |
133533520313147 has 2 divisors, whose sum is σ = 133533520313148. Its totient is φ = 133533520313146.
The previous prime is 133533520313093. The next prime is 133533520313239. The reversal of 133533520313147 is 741313025335331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133533520313147 - 218 = 133533520051003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133533520313098 and 133533520313107.
It is not a weakly prime, because it can be changed into another prime (133533520303147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66766760156573 + 66766760156574.
It is an arithmetic number, because the mean of its divisors is an integer number (66766760156574).
Almost surely, 2133533520313147 is an apocalyptic number.
133533520313147 is a deficient number, since it is larger than the sum of its proper divisors (1).
133533520313147 is an equidigital number, since it uses as much as digits as its factorization.
133533520313147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1020600, while the sum is 44.
Adding to 133533520313147 its reverse (741313025335331), we get a palindrome (874846545648478).
The spelling of 133533520313147 in words is "one hundred thirty-three trillion, five hundred thirty-three billion, five hundred twenty million, three hundred thirteen thousand, one hundred forty-seven".
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