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133534011114214 = 2337198121678211
BaseRepresentation
bin11110010111001011001111…
…010011000100001011100110
3122111210201121211101220010021
4132113023033103010023212
5120000310123321123324
61152000402224545354
740061341164430504
oct3627131723041346
9574721554356107
10133534011114214
113960350205a957
1212b8795218225a
13596828460b3b9
1424d911b32b674
1510687d5767ae4
hex7972cf4c42e6

133534011114214 has 8 divisors (see below), whose sum is σ = 200895381706968. Its totient is φ = 66568883878560.

The previous prime is 133534011114211. The next prime is 133534011114247. The reversal of 133534011114214 is 412411110435331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 133534011114214.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133534011114211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99060838432 + ... + 99060839779.

It is an arithmetic number, because the mean of its divisors is an integer number (25111922713371).

Almost surely, 2133534011114214 is an apocalyptic number.

133534011114214 is a deficient number, since it is larger than the sum of its proper divisors (67361370592754).

133534011114214 is a wasteful number, since it uses less digits than its factorization.

133534011114214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 198121678550.

The product of its (nonzero) digits is 17280, while the sum is 34.

Adding to 133534011114214 its reverse (412411110435331), we get a palindrome (545945121549545).

The spelling of 133534011114214 in words is "one hundred thirty-three trillion, five hundred thirty-four billion, eleven million, one hundred fourteen thousand, two hundred fourteen".

Divisors: 1 2 337 674 198121678211 396243356422 66767005557107 133534011114214