1335341120115 has 128 divisors (see below), whose sum is σ = 2291908608000. Its totient is φ = 661991616000.

The previous prime is 1335341120089. The next prime is 1335341120117. The reversal of 1335341120115 is 5110211435331.

It is not a de Polignac number, because 1335341120115 - 2¹⁸ = 1335340857971 is a prime.

It is a super-2 number, since 2×1335341120115² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1335341120117) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1419065545 + ... + 1419066485.

It is an arithmetic number, because the mean of its divisors is an integer number (17905536000).

Almost surely, 2^{1335341120115} is an apocalyptic number.

1335341120115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1335341120115 is a deficient number, since it is larger than the sum of its proper divisors (956567487885).

1335341120115 is a wasteful number, since it uses less digits than its factorization.

1335341120115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1489.

The product of its (nonzero) digits is 5400, while the sum is 30.

Adding to 1335341120115 its reverse (5110211435331), we get a palindrome (6445552555446).

The spelling of 1335341120115 in words is "one trillion, three hundred thirty-five billion, three hundred forty-one million, one hundred twenty thousand, one hundred fifteen".