Base | Representation |
---|---|
bin | 1100001001010001011100… |
… | …1000001101001011011011 |
3 | 1202021120120021202102212022 |
4 | 3002110113020031023123 |
5 | 3222240321441202423 |
6 | 44222253011205055 |
7 | 2545516503455162 |
oct | 302242710151333 |
9 | 52246507672768 |
10 | 13353441350363 |
11 | 4289187578554 |
12 | 15b7ba05a678b |
13 | 75b2bb4c9c1a |
14 | 34244a94a3d9 |
15 | 1825488aedc8 |
hex | c251720d2db |
13353441350363 has 2 divisors, whose sum is σ = 13353441350364. Its totient is φ = 13353441350362.
The previous prime is 13353441350281. The next prime is 13353441350413. The reversal of 13353441350363 is 36305314435331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13353441350363 - 28 = 13353441350107 is a prime.
It is a super-3 number, since 3×133534413503633 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13353441353363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676720675181 + 6676720675182.
It is an arithmetic number, because the mean of its divisors is an integer number (6676720675182).
Almost surely, 213353441350363 is an apocalyptic number.
13353441350363 is a deficient number, since it is larger than the sum of its proper divisors (1).
13353441350363 is an equidigital number, since it uses as much as digits as its factorization.
13353441350363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1749600, while the sum is 44.
Adding to 13353441350363 its reverse (36305314435331), we get a palindrome (49658755785694).
The spelling of 13353441350363 in words is "thirteen trillion, three hundred fifty-three billion, four hundred forty-one million, three hundred fifty thousand, three hundred sixty-three".
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