Base | Representation |
---|---|
bin | 1100001001010001011100… |
… | …1000001101111010010011 |
3 | 1202021120120021202120222102 |
4 | 3002110113020031322103 |
5 | 3222240321441301423 |
6 | 44222253011231015 |
7 | 2545516503500006 |
oct | 302242710157223 |
9 | 52246507676872 |
10 | 13353441353363 |
11 | 428918757a831 |
12 | 15b7ba05a846b |
13 | 75b2bb4cb3b7 |
14 | 34244a94b53d |
15 | 1825488b0c28 |
hex | c251720de93 |
13353441353363 has 2 divisors, whose sum is σ = 13353441353364. Its totient is φ = 13353441353362.
The previous prime is 13353441353311. The next prime is 13353441353423. The reversal of 13353441353363 is 36335314435331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13353441353363 - 218 = 13353441091219 is a prime.
It is a super-3 number, since 3×133534413533633 (a number of 40 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13353441350363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676720676681 + 6676720676682.
It is an arithmetic number, because the mean of its divisors is an integer number (6676720676682).
Almost surely, 213353441353363 is an apocalyptic number.
13353441353363 is a deficient number, since it is larger than the sum of its proper divisors (1).
13353441353363 is an equidigital number, since it uses as much as digits as its factorization.
13353441353363 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5248800, while the sum is 47.
Adding to 13353441353363 its reverse (36335314435331), we get a palindrome (49688755788694).
The spelling of 13353441353363 in words is "thirteen trillion, three hundred fifty-three billion, four hundred forty-one million, three hundred fifty-three thousand, three hundred sixty-three".
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