Base | Representation |
---|---|
bin | 1100001001010001011101… |
… | …1000001010001011111110 |
3 | 1202021120120120121220120002 |
4 | 3002110113120022023332 |
5 | 3222240324024014124 |
6 | 44222253240554302 |
7 | 2545516554143561 |
oct | 302242730121376 |
9 | 52246516556502 |
10 | 13353445532414 |
11 | 4289189974599 |
12 | 15b7ba1a82992 |
13 | 75b2bc332600 |
14 | 34244b3184d8 |
15 | 182548e390ae |
hex | c251760a2fe |
13353445532414 has 12 divisors (see below), whose sum is σ = 21689472181896. Its totient is φ = 6163128707112.
The previous prime is 13353445532411. The next prime is 13353445532429. The reversal of 13353445532414 is 41423554435331.
It is a super-3 number, since 3×133534455324143 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13353445532411) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 19753617314 + ... + 19753617989.
It is an arithmetic number, because the mean of its divisors is an integer number (1807456015158).
Almost surely, 213353445532414 is an apocalyptic number.
13353445532414 is a deficient number, since it is larger than the sum of its proper divisors (8336026649482).
13353445532414 is a wasteful number, since it uses less digits than its factorization.
13353445532414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39507235331 (or 39507235318 counting only the distinct ones).
The product of its digits is 5184000, while the sum is 47.
Adding to 13353445532414 its reverse (41423554435331), we get a palindrome (54776999967745).
The spelling of 13353445532414 in words is "thirteen trillion, three hundred fifty-three billion, four hundred forty-five million, five hundred thirty-two thousand, four hundred fourteen".
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