Base | Representation |
---|---|
bin | 1100001001010001011111… |
… | …1001111111011010110000 |
3 | 1202021120121012022111020122 |
4 | 3002110113321333122300 |
5 | 3222240333311314300 |
6 | 44222254155025412 |
7 | 2545520022422234 |
oct | 302242771773260 |
9 | 52246535274218 |
10 | 13353454401200 |
11 | 4289193981871 |
12 | 15b7ba4a3b268 |
13 | 75b2c1119304 |
14 | 34244c5865c4 |
15 | 182549adbc85 |
hex | c2517e7f6b0 |
13353454401200 has 60 divisors (see below), whose sum is σ = 32083843518960. Its totient is φ = 5341020583680.
The previous prime is 13353454401187. The next prime is 13353454401251. The reversal of 13353454401200 is 210445435331.
It is a super-2 number, since 2×133534544012002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4833566 + ... + 7076034.
It is an arithmetic number, because the mean of its divisors is an integer number (534730725316).
Almost surely, 213353454401200 is an apocalyptic number.
13353454401200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13353454401200 is an abundant number, since it is smaller than the sum of its proper divisors (18730389117760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13353454401200 is a wasteful number, since it uses less digits than its factorization.
13353454401200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2257374 (or 2257363 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 13353454401200 its reverse (210445435331), we get a palindrome (13563899836531).
The spelling of 13353454401200 in words is "thirteen trillion, three hundred fifty-three billion, four hundred fifty-four million, four hundred one thousand, two hundred".
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