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133538640067381 is a prime number
BaseRepresentation
bin11110010111001111100011…
…001101000111101100110101
3122111211011120102121002010011
4132113033203031013230311
5120000344113324124011
61152002445423300221
740061563663042003
oct3627174315075465
9574734512532104
10133538640067381
1139605467a7798a
1212b8882444a671
135968841625043
1424d943a003a73
1510689a6d29621
hex7973e3347b35

133538640067381 has 2 divisors, whose sum is σ = 133538640067382. Its totient is φ = 133538640067380.

The previous prime is 133538640067307. The next prime is 133538640067411. The reversal of 133538640067381 is 183760046835331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81170477605156 + 52368162462225 = 9009466^2 + 7236585^2 .

It is a cyclic number.

It is not a de Polignac number, because 133538640067381 - 219 = 133538639543093 is a prime.

It is a super-2 number, since 2×1335386400673812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133538640067981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66769320033690 + 66769320033691.

It is an arithmetic number, because the mean of its divisors is an integer number (66769320033691).

Almost surely, 2133538640067381 is an apocalyptic number.

It is an amenable number.

133538640067381 is a deficient number, since it is larger than the sum of its proper divisors (1).

133538640067381 is an equidigital number, since it uses as much as digits as its factorization.

133538640067381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26127360, while the sum is 58.

The spelling of 133538640067381 in words is "one hundred thirty-three trillion, five hundred thirty-eight billion, six hundred forty million, sixty-seven thousand, three hundred eighty-one".