Base | Representation |
---|---|
bin | 1100001001010011100010… |
… | …0111000111011101100110 |
3 | 1202021122000102210100121112 |
4 | 3002110320213013131212 |
5 | 3222242444243222132 |
6 | 44222424435345022 |
7 | 2545536434331545 |
oct | 302247047073546 |
9 | 52248012710545 |
10 | 13354003101542 |
11 | 4289445681524 |
12 | 15b8118752172 |
13 | 75b37a9c307c |
14 | 3424a13b815c |
15 | 18257cd74ab2 |
hex | c25389c7766 |
13354003101542 has 4 divisors (see below), whose sum is σ = 20031004652316. Its totient is φ = 6677001550770.
The previous prime is 13354003101469. The next prime is 13354003101577. The reversal of 13354003101542 is 24510130045331.
13354003101542 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 13354003101499 and 13354003101508.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3338500775384 + ... + 3338500775387.
It is an arithmetic number, because the mean of its divisors is an integer number (5007751163079).
Almost surely, 213354003101542 is an apocalyptic number.
13354003101542 is a deficient number, since it is larger than the sum of its proper divisors (6677001550774).
13354003101542 is an equidigital number, since it uses as much as digits as its factorization.
13354003101542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6677001550773.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 13354003101542 its reverse (24510130045331), we get a palindrome (37864133146873).
The spelling of 13354003101542 in words is "thirteen trillion, three hundred fifty-four billion, three million, one hundred one thousand, five hundred forty-two".
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