Base | Representation |
---|---|
bin | 1100001001010011100010… |
… | …1111010100110110100111 |
3 | 1202021122000120211200121021 |
4 | 3002110320233110312213 |
5 | 3222243000321103133 |
6 | 44222424553432011 |
7 | 2545536461533603 |
oct | 302247057246647 |
9 | 52248016750537 |
10 | 13354005253543 |
11 | 4289446911339 |
12 | 15b811940b607 |
13 | 75b37b297746 |
14 | 3424a17b8503 |
15 | 18257d14c52d |
hex | c2538bd4da7 |
13354005253543 has 2 divisors, whose sum is σ = 13354005253544. Its totient is φ = 13354005253542.
The previous prime is 13354005253517. The next prime is 13354005253553. The reversal of 13354005253543 is 34535250045331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13354005253543 - 213 = 13354005245351 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13354005253543.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13354005253513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6677002626771 + 6677002626772.
It is an arithmetic number, because the mean of its divisors is an integer number (6677002626772).
Almost surely, 213354005253543 is an apocalyptic number.
13354005253543 is a deficient number, since it is larger than the sum of its proper divisors (1).
13354005253543 is an equidigital number, since it uses as much as digits as its factorization.
13354005253543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620000, while the sum is 43.
Adding to 13354005253543 its reverse (34535250045331), we get a palindrome (47889255298874).
The spelling of 13354005253543 in words is "thirteen trillion, three hundred fifty-four billion, five million, two hundred fifty-three thousand, five hundred forty-three".
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