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13354005253543 is a prime number
BaseRepresentation
bin1100001001010011100010…
…1111010100110110100111
31202021122000120211200121021
43002110320233110312213
53222243000321103133
644222424553432011
72545536461533603
oct302247057246647
952248016750537
1013354005253543
114289446911339
1215b811940b607
1375b37b297746
143424a17b8503
1518257d14c52d
hexc2538bd4da7

13354005253543 has 2 divisors, whose sum is σ = 13354005253544. Its totient is φ = 13354005253542.

The previous prime is 13354005253517. The next prime is 13354005253553. The reversal of 13354005253543 is 34535250045331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13354005253543 - 213 = 13354005245351 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13354005253543.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13354005253513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6677002626771 + 6677002626772.

It is an arithmetic number, because the mean of its divisors is an integer number (6677002626772).

Almost surely, 213354005253543 is an apocalyptic number.

13354005253543 is a deficient number, since it is larger than the sum of its proper divisors (1).

13354005253543 is an equidigital number, since it uses as much as digits as its factorization.

13354005253543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620000, while the sum is 43.

Adding to 13354005253543 its reverse (34535250045331), we get a palindrome (47889255298874).

The spelling of 13354005253543 in words is "thirteen trillion, three hundred fifty-four billion, five million, two hundred fifty-three thousand, five hundred forty-three".