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13354120131017 is a prime number
BaseRepresentation
bin1100001001010011111110…
…0101100011000111001001
31202021122022121000001212112
43002110333211203013021
53222243214223143032
644222444215552105
72545542355141421
oct302247745430711
952248277001775
1013354120131017
1142894a57444a6
1215b814b98b635
1375b399019b93
143424b2b5d481
151825882901b2
hexc253f9631c9

13354120131017 has 2 divisors, whose sum is σ = 13354120131018. Its totient is φ = 13354120131016.

The previous prime is 13354120130999. The next prime is 13354120131061. The reversal of 13354120131017 is 71013102145331.

13354120131017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11792829896761 + 1561290234256 = 3434069^2 + 1249516^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13354120131017 is a prime.

It is not a weakly prime, because it can be changed into another prime (13354120131067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6677060065508 + 6677060065509.

It is an arithmetic number, because the mean of its divisors is an integer number (6677060065509).

Almost surely, 213354120131017 is an apocalyptic number.

It is an amenable number.

13354120131017 is a deficient number, since it is larger than the sum of its proper divisors (1).

13354120131017 is an equidigital number, since it uses as much as digits as its factorization.

13354120131017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7560, while the sum is 32.

Adding to 13354120131017 its reverse (71013102145331), we get a palindrome (84367222276348).

The spelling of 13354120131017 in words is "thirteen trillion, three hundred fifty-four billion, one hundred twenty million, one hundred thirty-one thousand, seventeen".