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13354734787117 is a prime number
BaseRepresentation
bin1100001001010110010000…
…1110010001101000101101
31202021200220102120211112021
43002111210032101220231
53222300444101141432
644223025214110141
72545563530501623
oct302254416215055
952250812524467
1013354734787117
1142897906a2749
1215b82a17ab351
1375b466477709
1434253063d513
151825c2205697
hexc2564391a2d

13354734787117 has 2 divisors, whose sum is σ = 13354734787118. Its totient is φ = 13354734787116.

The previous prime is 13354734787099. The next prime is 13354734787139. The reversal of 13354734787117 is 71178743745331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10763838927241 + 2590895859876 = 3280829^2 + 1609626^2 .

It is an emirp because it is prime and its reverse (71178743745331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13354734787117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13354734787717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6677367393558 + 6677367393559.

It is an arithmetic number, because the mean of its divisors is an integer number (6677367393559).

Almost surely, 213354734787117 is an apocalyptic number.

It is an amenable number.

13354734787117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13354734787117 is an equidigital number, since it uses as much as digits as its factorization.

13354734787117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41489280, while the sum is 61.

The spelling of 13354734787117 in words is "thirteen trillion, three hundred fifty-four billion, seven hundred thirty-four million, seven hundred eighty-seven thousand, one hundred seventeen".